GCSE Chemistry, Unit 3, Lesson 6 of 6

Concentration in mol/dm³, titrations and gas volumes

GCSE Chemistry, Quantitative chemistry and the mole, 25 minutes

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Moles in a solution, working out an unknown concentration from a titration, and the volume one mole of any gas takes up at room temperature and pressure.

What you will learn

  • Calculate concentration, moles or mass with mol/dm³, and convert to g/dm³
  • Pick concordant titres, find the mean and calculate an unknown concentration
  • Calculate gas volumes at RTP using 24 dm³ per mole

Concentration in mol/dm³

Concentration can be given in moles of solute per dm³ of solution.

concentration (mol/dm³) = moles of solute ÷ volume (dm³)
moles = concentration × volume (dm³)
concentration (g/dm³) = concentration (mol/dm³) × Mr

All boards (Chemistry only, Higher): recall these.

  1. 0.050 mol of NaOH in 250 cm³ of solution
  2. 250 cm³ = 0.250 dm³
  3. concentration = 0.050 ÷ 0.250 = 0.20 mol/dm³
  4. in g/dm³: 0.20 × 40 = 8.0 g/dm³

The rest of this lesson and its 15 practice questions are locked.

In this lesson

  1. Concentration in mol/dm³
  2. Titration calculations
  3. Volumes of gases
  4. Try it: Your first mol/dm³

15 practice questions, marked as you go; about 25 minutes in all.

Key terms

Concordant, Any

In this unit: Quantitative chemistry and the mole

Conservation of mass, relative formula mass, percentages and concentrations, the mole, reacting masses, empirical formulae, yield, atom economy, titrations and gas volumes.

All of Quantitative chemistry and the mole