GCSE Chemistry, Unit 7, Lesson 6 of 7
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Calculations with fuels and organic compounds

GCSE Chemistry, Organic chemistry, 25 minutes

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Mr and the percentage of carbon in a hydrocarbon or alcohol, moles and masses of carbon dioxide from burning a fuel, gas volumes, and estimating boiling points from a homologous series.

Mr and percentage of carbon

Add up the relative atomic masses of every atom in the formula.

Then:

percentage of carbon = (12 × number of C atoms) ÷ Mr × 100

You must recall this: there is no chemistry equation sheet.

  1. Hexane, C₆H₁₄ (C = 12, H = 1)
  2. Mr = 6 × 12 + 14 × 1 = 86
  3. mass of carbon = 6 × 12 = 72
  4. % carbon = 72 ÷ 86 × 100 = 83.7 % (1 d.p.)

Multiply 12 by the number of carbon atoms. 12 ÷ 86 × 100 gives 14.0 %, which is far too low for a hydrocarbon.

The rest of this lesson and its 10 practice questions are in Plus.

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  • 10 exam-style questions, marked as you go, each with a worked solution
  • The Molar Mass Calculator beside every question
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